4x^2-28x+24=0

解

4 x^{2} - 28 x + 24 = 0

x = 6, x = 1

解答ステップ

4 x^{2} - 28 x + 24 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 24}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 24 = 20

x_{1, 2} = \frac{- ( - 28 ) \pm 20}{2 \cdot 4}

解を分離する

x_{1} = \frac{- ( - 28 ) + 20}{2 \cdot 4}, x_{2} = \frac{- ( - 28 ) - 20}{2 \cdot 4}

x = \frac{- ( - 28 ) + 20}{2 \cdot 4} : 6

x = \frac{- ( - 28 ) - 20}{2 \cdot 4} : 1

二次equationの解:

x = 6, x = 1