What are the solutions to the equation 4v^2+25=-20v ?

The solutions to the equation 4v^2+25=-20v are v=-5/2

Find the zeros of 4v^2+25=-20v

The zeros of 4v^2+25=-20v are v=-5/2

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4 v^{2} + 25 = - 20 v

v = - \frac{5}{2}

Decimal

v = - 2.5

Solution steps

4 v^{2} + 25 = - 20 v

Move

20 v

to the left side

4 v^{2} + 25 + 20 v = 0

Write in the standard form

a x^{2} + b x + c = 0

4 v^{2} + 20 v + 25 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

v_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

v = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

v = - \frac{5}{2}

The solution to the quadratic equation is:

v = - \frac{5}{2}

\frac{3}{5} \cdot \frac{1}{2}

\frac{1}{6} + \frac{x + 2}{3} = 1

2 m - 1 > - 9

x - 12 = 13

\frac{3 x ^{2} - 2 x}{3 x + 2} \leq - 2

What are the solutions to the equation 4v^2+25=-20v ?
The solutions to the equation 4v^2+25=-20v are v=-5/2
Find the zeros of 4v^2+25=-20v
The zeros of 4v^2+25=-20v are v=-5/2