What is (3x^2-2x)/(3x+2)<=-2 ?

The solution to (3x^2-2x)/(3x+2)<=-2 is x<-2/3

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(3x^2-2x)/(3x+2)<=-2

\frac{3 x ^{2} - 2 x}{3 x + 2} \leq - 2

x < - \frac{2}{3}

Solution steps

\frac{3 x ^{2} - 2 x}{3 x + 2} \leq - 2

Rewrite in standard form

\frac{3 x ^{2} + 4 x + 4}{3 x + 2} \leq 0

Identify the intervals

x < - \frac{2}{3}

(x + 2)^{2} \leq 25

2 (2 c + 9) = c

\frac{8 0 ^{\frac{1}{4}}}{5 ^{- \frac{1}{4}}}

3 x^{3} + 23 x^{2} + 40 x - 16

- 5.3 \geq 6.7 + 4.3 + q