What are the solutions to the equation 4x^2+x+5=0 ?

The solutions to the equation 4x^2+x+5=0 are x=-1/8+i(sqrt(79))/8 ,x=-1/8-i(sqrt(79))/8

Find the zeros of 4x^2+x+5=0

The zeros of 4x^2+x+5=0 are x=-1/8+i(sqrt(79))/8 ,x=-1/8-i(sqrt(79))/8

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4 x^{2} + x + 5 = 0

x = - \frac{1}{8} + i \frac{79}{8}, x = - \frac{1}{8} - i \frac{79}{8}

Solution steps

4 x^{2} + x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

Simplify

1^{2} - 4 \cdot 4 \cdot 5 : 79 i

x_{1, 2} = \frac{- 1 \pm 79 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 79 i}{2 \cdot 4}, x_{2} = \frac{- 1 - 79 i}{2 \cdot 4}

x = \frac{- 1 + 79 i}{2 \cdot 4} : - \frac{1}{8} + i \frac{79}{8}

x = \frac{- 1 - 79 i}{2 \cdot 4} : - \frac{1}{8} - i \frac{79}{8}

The solutions to the quadratic equation are:

x = - \frac{1}{8} + i \frac{79}{8}, x = - \frac{1}{8} - i \frac{79}{8}

4 v^{2} + 25 = - 20 v

\frac{3}{5} \cdot \frac{1}{2}

\frac{1}{6} + \frac{x + 2}{3} = 1

2 m - 1 > - 9

x - 12 = 13

What are the solutions to the equation 4x^2+x+5=0 ?
The solutions to the equation 4x^2+x+5=0 are x=-1/8+i(sqrt(79))/8 ,x=-1/8-i(sqrt(79))/8
Find the zeros of 4x^2+x+5=0
The zeros of 4x^2+x+5=0 are x=-1/8+i(sqrt(79))/8 ,x=-1/8-i(sqrt(79))/8