What are the solutions to the equation 2x^2-7x+3=0 ?

The solutions to the equation 2x^2-7x+3=0 are x=3,x= 1/2

Find the zeros of 2x^2-7x+3=0

The zeros of 2x^2-7x+3=0 are x=3,x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 7 x + 3 = 0

x = 3, x = \frac{1}{2}

Decimal Notation

x = 3, x = 0.5

Solution steps

2 x^{2} - 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 3 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 2}

x = \frac{- ( - 7 ) + 5}{2 \cdot 2} : 3

x = \frac{- ( - 7 ) - 5}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = \frac{1}{2}

(- 2 r^{4} s^{- 3})^{- 2}

(2 x - 12) x = 0

2 - x^{3} \geq 10

0 = - 36 + 13.21 x + \frac{1}{2} (9.8) x^{2}

\frac{1 - \frac{y}{y + x}}{1 - \frac{y}{y - x}}

What are the solutions to the equation 2x^2-7x+3=0 ?
The solutions to the equation 2x^2-7x+3=0 are x=3,x= 1/2
Find the zeros of 2x^2-7x+3=0
The zeros of 2x^2-7x+3=0 are x=3,x= 1/2