What is (-2r^4s^{-3})^{-2} ?

The solution to (-2r^4s^{-3})^{-2} is (s^6)/(4r^8)

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simplify (-2r^4s^{-3})^{-2}

simplify

(- 2 r^{4} s^{- 3})^{- 2}

\frac{s ^{6}}{4 r ^{8}}

Solution steps

(- 2 r^{4} s^{- 3})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(- 2 r^{4} s^{- 3})^{- 2} = \frac{1}{( - 2 r ^{4} s ^{- 3} ) ^{2}}

= \frac{1}{( - 2 r ^{4} s ^{- 3} ) ^{2}}

Simplify

(- 2 r^{4} s^{- 3})^{2} : \frac{4 r ^{8}}{s ^{6}}

= \frac{1}{\frac{4 r ^{8}}{s ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{s ^{6}}{4 r ^{8}}

(2 x - 12) x = 0

2 - x^{3} \geq 10

0 = - 36 + 13.21 x + \frac{1}{2} (9.8) x^{2}

\frac{1 - \frac{y}{y + x}}{1 - \frac{y}{y - x}}

- (\frac{36}{49})^{\frac{1}{2}}