What is e^{(2pii)/6} ?

The solution to e^{(2pii)/6} is 1/2+i(sqrt(3))/2

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simplify e^{(2pii)/6}

simplify

e^{\frac{2 πi}{6}}

\frac{1}{2} + i \frac{3}{2}

Solution steps

e^{\frac{2 πi}{6}}

\frac{2 πi}{6} = \frac{πi}{3}

= e^{\frac{πi}{3}}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= cos (\frac{π}{3}) + i sin (\frac{π}{3})

Use the following trivial identity:

cos (\frac{π}{3}) = \frac{1}{2}

Use the following trivial identity:

sin (\frac{π}{3}) = \frac{3}{2}

= \frac{1}{2} + i \frac{3}{2}

Multiply

\frac{3}{2} i : \frac{3 i}{2}

= \frac{1}{2} + \frac{3 i}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 3 i}{2}

Rewrite

\frac{1 + 3 i}{2}

in standard complex form:

\frac{1}{2} + \frac{3}{2} i

= \frac{1}{2} + \frac{3}{2} i

\frac{1}{∣ x ∣ - 7} < - 1

207

x^{2} - 4 x - 4 = 0

- 8 = 9 - 5 h

d = \frac{10.2}{36 + ( 10.2 ) ^{2}} (440)