What is 1/(|x|-7)<-1 ?

The solution to 1/(|x|-7)<-1 is -7<x<-6\lor 6<x<7

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1/(|x|-7)<-1

\frac{1}{∣ x ∣ - 7} < - 1

- 7 < x < - 6 or 6 < x < 7

Interval Notation

(- 7, - 6) \cup (6, 7)

Solution steps

\frac{1}{∣ x ∣ - 7} < - 1

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

No Solution or - 7 < x < - 6 or 6 < x < 7

Merge Overlapping Intervals

- 7 < x < - 6 or 6 < x < 7

207

x^{2} - 4 x - 4 = 0

- 8 = 9 - 5 h

d = \frac{10.2}{36 + ( 10.2 ) ^{2}} (440)

18 \geq 5 k + 4 k