What are the solutions to the equation 2(3a^2-1)-6a=5a ?

The solutions to the equation 2(3a^2-1)-6a=5a are a=2,a=-1/6

Find the zeros of 2(3a^2-1)-6a=5a

The zeros of 2(3a^2-1)-6a=5a are a=2,a=-1/6

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2 (3 a^{2} - 1) - 6 a = 5 a

a = 2, a = - \frac{1}{6}

Decimal Notation

a = 2, a = - 0.16666 \dots

Solution steps

2 (3 a^{2} - 1) - 6 a = 5 a

Expand

2 (3 a^{2} - 1) - 6 a : 6 a^{2} - 2 - 6 a

6 a^{2} - 2 - 6 a = 5 a

Move

5 a

to the left side

6 a^{2} - 2 - 11 a = 0

Write in the standard form

a x^{2} + b x + c = 0

6 a^{2} - 11 a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 (- 2) = 13

a_{1, 2} = \frac{- ( - 11 ) \pm 13}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- ( - 11 ) + 13}{2 \cdot 6}, a_{2} = \frac{- ( - 11 ) - 13}{2 \cdot 6}

a = \frac{- ( - 11 ) + 13}{2 \cdot 6} : 2

a = \frac{- ( - 11 ) - 13}{2 \cdot 6} : - \frac{1}{6}

The solutions to the quadratic equation are:

a = 2, a = - \frac{1}{6}

(2 + i)^{2} - (4 - i)^{2}

x - 4 \geq 1

(x - 4) (3 x + 2) = 0

4 - \frac{2}{7} w = 18

\frac{3 π}{2} + 2 π

What are the solutions to the equation 2(3a^2-1)-6a=5a ?
The solutions to the equation 2(3a^2-1)-6a=5a are a=2,a=-1/6
Find the zeros of 2(3a^2-1)-6a=5a
The zeros of 2(3a^2-1)-6a=5a are a=2,a=-1/6