What are the solutions to the equation (x-4)(3x+2)=0 ?

The solutions to the equation (x-4)(3x+2)=0 are x=4,x=-2/3

Find the zeros of (x-4)(3x+2)=0

The zeros of (x-4)(3x+2)=0 are x=4,x=-2/3

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(x - 4) (3 x + 2) = 0

x = 4, x = - \frac{2}{3}

Decimal Notation

x = 4, x = - 0.66666 \dots

Solution steps

(x - 4) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or 3 x + 2 = 0

Solve

x - 4 = 0 : x = 4

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{2}{3}

4 - \frac{2}{7} w = 18

\frac{3 π}{2} + 2 π

d^{2} - 22 d + 21 = 0

(\frac{1}{2})^{4}

\frac{1}{\frac{- 1}{2}}

What are the solutions to the equation (x-4)(3x+2)=0 ?
The solutions to the equation (x-4)(3x+2)=0 are x=4,x=-2/3
Find the zeros of (x-4)(3x+2)=0
The zeros of (x-4)(3x+2)=0 are x=4,x=-2/3