What are the solutions to the equation 5x^2+4x+8=0 ?

The solutions to the equation 5x^2+4x+8=0 are x=-2/5+i 6/5 ,x=-2/5-i 6/5

Find the zeros of 5x^2+4x+8=0

The zeros of 5x^2+4x+8=0 are x=-2/5+i 6/5 ,x=-2/5-i 6/5

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5 x^{2} + 4 x + 8 = 0

x = - \frac{2}{5} + i \frac{6}{5}, x = - \frac{2}{5} - i \frac{6}{5}

Solution steps

5 x^{2} + 4 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 8 : 12 i

x_{1, 2} = \frac{- 4 \pm 12 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 12 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 12 i}{2 \cdot 5}

x = \frac{- 4 + 12 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{6}{5}

x = \frac{- 4 - 12 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{6}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{6}{5}, x = - \frac{2}{5} - i \frac{6}{5}

4 x^{2} - 12 x = 16

p^{2} + 2 p (0.06) + 0.36 = 1

15 x^{2} + 29 x + 12

- 1 \leq x - 2 \leq 4

4 x - 6 = 3 x

What are the solutions to the equation 5x^2+4x+8=0 ?
The solutions to the equation 5x^2+4x+8=0 are x=-2/5+i 6/5 ,x=-2/5-i 6/5
Find the zeros of 5x^2+4x+8=0
The zeros of 5x^2+4x+8=0 are x=-2/5+i 6/5 ,x=-2/5-i 6/5