What are the solutions to the equation 4x^2-12x=16 ?

The solutions to the equation 4x^2-12x=16 are x=4,x=-1

Find the zeros of 4x^2-12x=16

The zeros of 4x^2-12x=16 are x=4,x=-1

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4 x^{2} - 12 x = 16

x = 4, x = - 1

Solution steps

4 x^{2} - 12 x = 16

Move

16

to the left side

4 x^{2} - 12 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 16) = 20

x_{1, 2} = \frac{- ( - 12 ) \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 20}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 20}{2 \cdot 4}

x = \frac{- ( - 12 ) + 20}{2 \cdot 4} : 4

x = \frac{- ( - 12 ) - 20}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

p^{2} + 2 p (0.06) + 0.36 = 1

15 x^{2} + 29 x + 12

- 1 \leq x - 2 \leq 4

4 x - 6 = 3 x

\frac{2 a ^{- 1} b ^{4} \cdot 2 a ^{0} b ^{0}}{b ^{4}}

What are the solutions to the equation 4x^2-12x=16 ?
The solutions to the equation 4x^2-12x=16 are x=4,x=-1
Find the zeros of 4x^2-12x=16
The zeros of 4x^2-12x=16 are x=4,x=-1