What are the solutions to the equation (x+4)^2-4=16 ?

The solutions to the equation (x+4)^2-4=16 are x=2sqrt(5)-4,x=-2sqrt(5)-4

Find the zeros of (x+4)^2-4=16

The zeros of (x+4)^2-4=16 are x=2sqrt(5)-4,x=-2sqrt(5)-4

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(x + 4)^{2} - 4 = 16

x = 25 - 4, x = - 25 - 4

Decimal Notation

x = 0.47213 \dots, x = - 8.47213 \dots

Solution steps

(x + 4)^{2} - 4 = 16

Move

4

to the right side

(x + 4)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 20 : x = 25 - 4

Solve

x + 4 = - 20 : x = - 25 - 4

The solutions to the quadratic equation are:

x = 25 - 4, x = - 25 - 4

\frac{( 3 - 2 i )}{( - 2 + 7 i )}

(x + 6)^{2}

- ln (4)

5.5 \cdot 0.4 = \frac{3}{44} \cdot 0.082 \cdot T

\frac{x}{2} \geq \frac{35}{x + 1} + 1

What are the solutions to the equation (x+4)^2-4=16 ?
The solutions to the equation (x+4)^2-4=16 are x=2sqrt(5)-4,x=-2sqrt(5)-4
Find the zeros of (x+4)^2-4=16
The zeros of (x+4)^2-4=16 are x=2sqrt(5)-4,x=-2sqrt(5)-4