What are the solutions to the equation x^2+28x+147=0 ?

The solutions to the equation x^2+28x+147=0 are x=-7,x=-21

Find the zeros of x^2+28x+147=0

The zeros of x^2+28x+147=0 are x=-7,x=-21

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x^{2} + 28 x + 147 = 0

x = - 7, x = - 21

Solution steps

x^{2} + 28 x + 147 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 1 \cdot 147}{2 \cdot 1}

2 8^{2} - 4 \cdot 1 \cdot 147 = 14

x_{1, 2} = \frac{- 28 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 28 + 14}{2 \cdot 1}, x_{2} = \frac{- 28 - 14}{2 \cdot 1}

x = \frac{- 28 + 14}{2 \cdot 1} : - 7

x = \frac{- 28 - 14}{2 \cdot 1} : - 21

The solutions to the quadratic equation are:

x = - 7, x = - 21

- 3 x - 6 > 3 x + 6

(2 - i) \cdot z + i = 2

6 x^{2} + x - 1 = 0

5 x^{2} = 8 x + 6

4800 = \frac{1}{3} s^{2} 25

What are the solutions to the equation x^2+28x+147=0 ?
The solutions to the equation x^2+28x+147=0 are x=-7,x=-21
Find the zeros of x^2+28x+147=0
The zeros of x^2+28x+147=0 are x=-7,x=-21