What are the solutions to the equation 6x^2+x-1=0 ?

The solutions to the equation 6x^2+x-1=0 are x= 1/3 ,x=-1/2

Find the zeros of 6x^2+x-1=0

The zeros of 6x^2+x-1=0 are x= 1/3 ,x=-1/2

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6 x^{2} + x - 1 = 0

x = \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = 0.33333 \dots, x = - 0.5

Solution steps

6 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 6}, x_{2} = \frac{- 1 - 5}{2 \cdot 6}

x = \frac{- 1 + 5}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 1 - 5}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{1}{2}

5 x^{2} = 8 x + 6

4800 = \frac{1}{3} s^{2} 25

z, B = \frac{1}{2} f (r + z)

3 x - 5 = - 26

(3 q^{2} - 12 q + 20) = 0

What are the solutions to the equation 6x^2+x-1=0 ?
The solutions to the equation 6x^2+x-1=0 are x= 1/3 ,x=-1/2
Find the zeros of 6x^2+x-1=0
The zeros of 6x^2+x-1=0 are x= 1/3 ,x=-1/2