化简 1/((2a-b)(a-c))+1/((b-c)(b-2a))

解答

化简

\frac{1}{( 2 a - b ) ( a - c )} + \frac{1}{( b - c ) ( b - 2 a )}

- \frac{- b + a}{( a - c ) ( b - c ) ( 2 a - b )}

求解步骤

\frac{1}{( 2 a - b ) ( a - c )} + \frac{1}{( b - c ) ( b - 2 a )}

(2 a - b) (a - c), (b - c) (b - 2 a)

的最小公倍数:

- (a - c) (b - c) (2 a - b)

根据最小公倍数调整分式

= \frac{- b + c}{- ( a - c ) ( b - c ) ( 2 a - b )} + \frac{- c + a}{- ( a - c ) ( b - c ) ( 2 a - b )}

使用分式法则:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{- b + c - c + a}{- ( a - c ) ( b - c ) ( 2 a - b )}

9 d + d - 3 d = 14

s im pl i f y \frac{5}{8} - \frac{1}{3}

s im pl i f y 45 x^{3} y^{8}

f a c t or 20 x^{2} + 3 x y - 2 y^{2}

f a c t or 8 y^{4} + x^{3} y