What is (x+1)/(x-6)>= (x+2)/(x-4) ?

The solution to (x+1)/(x-6)>= (x+2)/(x-4) is -8 6

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(x+1)/(x-6)>= (x+2)/(x-4)

\frac{x + 1}{x - 6} \geq \frac{x + 2}{x - 4}

- 8 \leq x < 4 or x > 6

Interval Notation

[- 8, 4) \cup (6, \infty)

Solution steps

\frac{x + 1}{x - 6} \geq \frac{x + 2}{x - 4}

Rewrite in standard form

\frac{x + 8}{( x - 6 ) ( x - 4 )} \geq 0

Identify the intervals

- 8 \leq x < 4 or x > 6

x^{2} + 9 x y + 14 y^{2}

28 c - 12

p (40) = 100 (0.92)^{40}

x^{3} + 2 x^{2} + 5 x

n^{2} - 10 n + 22 = - 2

What is (x+1)/(x-6)>= (x+2)/(x-4) ?
The solution to (x+1)/(x-6)>= (x+2)/(x-4) is -8<= x<4\lor x>6