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Popular Word Problems >

Two cyclists leave towns 156 kilometers apart at the same time and travel toward each other. One cyclist travels 3kph slower than the other. If they meet in 4 hours, what is the rate of each cyclist?

Solution

Tw o cyc l i s t s l e a v e t o w n s 156 ki l o m e t ers a p a r t a t t h e s am e t im e an d t r a v e l t o w a r d e a c h o t h er . O n e cyc l i s t t r a v e l s 3 k p h s l o w er t han t h e o t h er . I f t h ey m ee t in 4 h o u rs, w ha t i s t h e r a t e o f e a c h cyc l i s t ?

Solution

first cyclis t^{'} s speed : 18

second cyclis t^{'} s speed : 21

Solution steps

Translate the problem into an equation:

x \cdot 4 + (x + 3) \cdot 4 = 156

Solve for

x, x \cdot 4 + (x + 3) \cdot 4 = 156 : x = 18

Find speed

first cyclis t^{'} s speed : 18

second cyclis t^{'} s speed : 21

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