The sum of two numbers is 42. Three times the smaller number is 9 more than twice the larger number. Find the numbers

解

T h e s u m o f tw o n u mb ers i s 42. T h ree t im es t h e s ma ll er n u mb er i s 9 m ore t han tw i ce t h e l a r g er n u mb er . F in d t h e n u mb ers

The numbers : 18 \frac{3}{5}, 23 \frac{2}{5}

解答ステップ

Represent the numbers with

x and y

number 1 : x

number 2 : y

A.T.Q.:

x + y = 42

3 x = 9 + 2 y

x + y = 42, 3 x = 9 + 2 y : x = \frac{93}{5}, y = \frac{117}{5}

仮分数を帯分数に変換する:

\frac{93}{5} = 18 \frac{3}{5}

仮分数を帯分数に変換する:

\frac{117}{5} = 23 \frac{2}{5}

The numbers : 18 \frac{3}{5}, 23 \frac{2}{5}