Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 65 km/h faster than the other. If the two planes are 14175 kilometers apart after 9 hours, what is the rate of each plane?

Solution

Tw o ai r pl an es l e a v e an ai r p or t a t t h e s am e t im e an d t r a v e l in o pp os i t e d i rec t i o n s . O n e pl an e t r a v e l s 65 km / h f a s t er t han t h e o t h er . I f t h e tw o pl an es a re 14175 ki l o m e t ers a p a r t a f t er 9 h o u rs, w ha t i s t h e r a t e o f e a c h pl an e ?

first plan e^{'} s speed : 820

second plan e^{'} s speed : 755

Solution steps

Translate the problem into an equation:

x \cdot 9 + (x - 65) \cdot 9 = 14175

Solve for

x, x \cdot 9 + (x - 65) \cdot 9 = 14175 : x = 820

Find speed

first plan e^{'} s speed : 820

second plan e^{'} s speed : 755