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Popular Word Problems >

Find two positive even consecutive integers such that the square of the smaller integer is 10 more than the larger integer.

Solution

solve for

tw o p os i t i v e e v e n co n sec u t i v e in t e g ers s u c h t ha t t h e s q u a re o f t h e s ma ll er in t e g er i s 10 m ore t han t h e l a r g er in t e g er .

Solution

The number : 2 \frac{1}{2} or - 2

Solution steps

Represent the number with

x

A.T.Q.:

2 x^{2} = 10 + x

Solve for

x, 2 x^{2} = 10 + x : x = \frac{5}{2}, x = - 2

Convert improper fractions to mixed numbers:

\frac{5}{2} = 2 \frac{1}{2}

The number : 2 \frac{1}{2} or - 2

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