in a game, a player tosses a coin four times, what is the probability of getting two heads?

解

in a g am e, a pl a yer t osses a co in f o u r t im es, w ha t i s t h e p ro babi l i t y o f g e tt in g tw o h e a d s ?

\frac{3}{8}

十進法表記

0.375

解答ステップ

The possible outcomes when a coin is thrown four times are

2 \cdot 2 \cdot 2 \cdot 2

Therefore, the number of possible outcomes:

2^{4}

Find the number of favorable outcomes of getting 2 heads:

6

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{6}{2 ^{4}}

\frac{6}{2 ^{4}} = \frac{3}{8}

= \frac{3}{8}