sum of three consecutive numbers are is 248 find the numbers

解

s u m o f t h ree co n sec u t i v e n u mb ers a re i s 248 f in d t h e n u mb ers

The numbers : 81 \frac{2}{3}, 82 \frac{2}{3}, 83 \frac{2}{3}

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

x + x + 1 + x + 2 = 248

解く

x + x + 1 + x + 2 = 248 : x = \frac{245}{3}

x + 1 = \frac{245}{3} + 1 = \frac{248}{3}

x + 2 = \frac{245}{3} + 2 = \frac{251}{3}

仮分数を帯分数に変換する:

\frac{245}{3} = 81 \frac{2}{3}

仮分数を帯分数に変換する:

\frac{248}{3} = 82 \frac{2}{3}

仮分数を帯分数に変換する:

\frac{251}{3} = 83 \frac{2}{3}

The numbers : 81 \frac{2}{3}, 82 \frac{2}{3}, 83 \frac{2}{3}