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Popular Word Problems >

If the sum of six consecutive odd integers is 252, what is the smallest of the six integers?

Solution

I f t h e s u m o f s i x co n sec u t i v e o dd in t e g ers i s 252, w ha t i s t h e s ma ll es t o f t h e s i x in t e g ers ?

Solution

The smallest number : 37

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

Consecutive number 4 : x + 8

Consecutive number 5 : x + 10

A.T.Q.:

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 252

Solve

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 252 : x = 37

x + 2 = 37 + 2 = 39

x + 4 = 37 + 4 = 41

x + 6 = 37 + 6 = 43

x + 8 = 37 + 8 = 45

x + 10 = 37 + 10 = 47

Select the smallest solution:

37

The smallest number : 37

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