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Popular >

If the sum of six consecutive odd integers is 252, what is the smallest of the six integers?

Solution

If the sum of six consecutive odd integers is 252, what is the smallest of the six integers?

Solution

The smallest number : 37

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

Consecutive number 4 : x + 8

Consecutive number 5 : x + 10

A.T.Q.:

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 252

Solve

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 252 : x = 37

x + 2 = 37 + 2 = 39

x + 4 = 37 + 4 = 41

x + 6 = 37 + 6 = 43

x + 8 = 37 + 8 = 45

x + 10 = 37 + 10 = 47

Select the smallest solution:

37

The smallest number : 37

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