A person invests 1000 dollars in a bank. The bank pays 5.75% interest compounded monthly. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 2900 dollars?

Lösung

A p erso n in v es t s 1000 d o ll a rs in a bank . T h e bank p a ys 5.75% in t eres t co m p o u n d e d m o n t h l y . T o t h e n e a res t t e n t h o f a ye a r, h o w l o n g m u s t t h e p erso n l e a v e t h e m o n ey in t h e bank u n t i l i t re a c h es 2900 d o ll a rs ?

Time : 18.56

Schritte zur Lösung

Translate the problem into an equation:

2900 = 1000 (1 + \frac{0.0575}{12})^{12 t}

Löse nach

t, 2900 = 1000 (1 + \frac{0.0575}{12})^{12 t} : t = 18.56

Time : 18.56