Two cyclists start at the same point and travel in opposite directions. One cyclist travels 4 miles per hour slower than the other. If the two cyclists are 60 miles apart after 2 hours, what is the rate of each cyclists?

Lösung

Tw o cyc l i s t s s t a r t a t t h e s am e p o in t an d t r a v e l in o pp os i t e d i rec t i o n s . O n e cyc l i s t t r a v e l s 4 mi l es p er h o u r s l o w er t han t h e o t h er . I f t h e tw o cyc l i s t s a re 60 mi l es a p a r t a f t er 2 h o u rs, w ha t i s t h e r a t e o f e a c h cyc l i s t s ?

first cyclis t^{'} s speed : 13

second cyclis t^{'} s speed : 17

Schritte zur Lösung

Translate the problem into an equation:

x \cdot 2 + (x + 4) \cdot 2 = 60

Löse nach

x, x \cdot 2 + (x + 4) \cdot 2 = 60 : x = 13

Finde speed

first cyclis t^{'} s speed : 13

second cyclis t^{'} s speed : 17