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1. The sum of three consecutive numbers is 112. Find the numbers.

الحلّ

1. The sum of three consecutive numbers is 112. Find the numbers.

الحلّ

The numbers : 36 \frac{1}{3}, 37 \frac{1}{3}, 38 \frac{1}{3}

خطوات الحلّ

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

x + x + 1 + x + 2 = 112

x + x + 1 + x + 2 = 112

حلّ:

x = \frac{109}{3}

x + 1 = \frac{109}{3} + 1 = \frac{112}{3}

x + 2 = \frac{109}{3} + 2 = \frac{115}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{109}{3} = 36 \frac{1}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{112}{3} = 37 \frac{1}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{115}{3} = 38 \frac{1}{3}

The numbers : 36 \frac{1}{3}, 37 \frac{1}{3}, 38 \frac{1}{3}

أمثلة شائعة

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