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受欢迎的 Word Problems >

tanh(1) :Enter a number.

解答

tanh (1)

解答

\frac{e ^{2} - 1}{e ^{2} + 1}

+1

十进制

0.76159 \dots

求解步骤

tanh (1)

使用双曲函数恒等式:

tanh (x) = \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

= \frac{e ^{1} - e ^{- 1}}{e ^{1} + e ^{- 1}}

\frac{e ^{1} - e ^{- 1}}{e ^{1} + e ^{- 1}} = \frac{e ^{2} - 1}{e ^{2} + 1}

= \frac{e ^{2} - 1}{e ^{2} + 1}

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