Two buses leave a station at the same time and travel in opposite directions . One bus travels 19 kilometers faster than the other. If the two buses are 1035 kilometers apart after 5 hours, what is the rate of each bus?

Solution

Tw o b u ses l e a v e a s t a t i o n a t t h e s am e t im e an d t r a v e l in o pp os i t e d i rec t i o n s . O n e b u s t r a v e l s 19 ki l o m e t ers f a s t er t han t h e o t h er . I f t h e tw o b u ses a re 1035 ki l o m e t ers a p a r t a f t er 5 h o u rs, w ha t i s t h e r a t e o f e a c h b u s ?

first bu s^{'} s speed : 113

second bu s^{'} s speed : 94

Solution steps

Translate the problem into an equation:

x \cdot 5 + (x - 19) \cdot 5 = 1035

Solve for

x, x \cdot 5 + (x - 19) \cdot 5 = 1035 : x = 113

Find speed

first bu s^{'} s speed : 113

second bu s^{'} s speed : 94