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Popular Word Problems >

Father's age is 7 times as old as his son. Two years ago; father was 13 times as old as his son. What are their present ages ?

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Solution

Father′sageis7timesasoldashisson.Twoyearsago;fatherwas13timesasoldashisson.Whataretheirpresentages?

Solution

Boy′sageis:4
Father′sageis:28
Solution steps
Translate the problem into an equation:7x−2=13(x−2)
Solve for x,7x−2=13(x−2):x=4
Find age
Boy′sageis:4
Father′sageis:28

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