en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Word Problems >

Nine years ago, Jareth was five times as old as Dave. Now, he is only three times as old as Dave. Find their present ages.

Solution

N in e ye a rs a g o, J a re t h w a s f i v e t im es a s o l d a s D a v e . N o w, h e i s o n l y t h ree t im es a s o l d a s D a v e . F in d t h e i r p rese n t a g es .

Solution

Dave^{'} s age is : 18

Jareth^{'} s age is : 54

Solution steps

Translate the problem into an equation:

3 x - 9 = 5 (x - 9)

Solve for

x, 3 x - 9 = 5 (x - 9) : x = 18

Find age

Dave^{'} s age is : 18

Jareth^{'} s age is : 54

Popular Examples

The sum of the ages of a father and son is 56. Four years ago the father was 3 times as old as the son. Find the present age of each.simplify Nine years ago, Jareth was five times as old as Dave. Now, he is only three times as old as Dave. Find their present ages.Melvin is 18 years older than his daughter, Melly. Eight years ago, he was 7 times as old as his daughter. Find the present age of Melly.Andrei is 6 years older than his sister Andrea. After 10 years, the sum of their ages will be 50. How old is Andrea?Carmen is 9 years older than David. Seven years ago, the sum of their ages was 25. How old are they now?