Find three consecutive integers such that 16 more than half of the larger number is two thirds of the smallest number.

해법

F in d t h ree co n sec u t i v e in t e g ers s u c h t ha t 16 m ore t han ha l f o f t h e l a r g er n u mb er i s tw o t hi r d s o f t h e s ma ll es t n u mb er .

The numbers : 102, 103, 104

솔루션 단계

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

16 + \frac{1}{2} (x + 2) = \frac{2}{3} x

16 + \frac{1}{2} (x + 2) = \frac{2}{3} x

해결 :

x = 102

x + 1 = 102 + 1 = 103

x + 2 = 102 + 2 = 104

The numbers : 102, 103, 104