Three numbers are in the ratio 1:3:7. if the sum of the three numbers is 320. what are the numbers?

解

T h ree n u mb ers a re in t h e r a t i o 1 : 3 : 7. i f t h e s u m o f t h e t h ree n u mb ers i s 320. w ha t a re t h e n u mb ers ?

The numbers : 29 \frac{1}{11}, 87 \frac{3}{11}, 203 \frac{7}{11}

解答ステップ

Represent the numbers in ratio 1:3:7 with

x

x

3 x

7 x

Write an equation for the sum:

x + 3 x + 7 x = 320

x

を解く

x + 3 x + 7 x = 320 : x = \frac{320}{11}

x = \frac{320}{11}

3 x = 3 \cdot \frac{320}{11} = \frac{960}{11}

7 x = 7 \cdot \frac{320}{11} = \frac{2240}{11}

仮分数を帯分数に変換する:

\frac{320}{11} = 29 \frac{1}{11}

仮分数を帯分数に変換する:

\frac{960}{11} = 87 \frac{3}{11}

仮分数を帯分数に変換する:

\frac{2240}{11} = 203 \frac{7}{11}

The numbers : 29 \frac{1}{11}, 87 \frac{3}{11}, 203 \frac{7}{11}