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4.A father is 7times as old as his son. Two years ago, the father was 13 times as old asa his son. What are their preaent ages?

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Solution

4.Afatheris7timesasoldashisson.Twoyearsago,thefatherwas13timesasoldasahisson.Whataretheirpreaentages?

Solution

Boy′sageis:4
Father′sageis:28
Solution steps
Translate the problem into an equation:7x−2=13(x−2)
Solve for x,7x−2=13(x−2):x=4
Find age
Boy′sageis:4
Father′sageis:28

Popular Examples

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