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A Father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present ages.

Solution

A Father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present ages.

Solution

Boy^{'} s age is : 18

Father^{'} s age is : 36

Solution steps

Translate the problem into an equation:

2 x - 12 = 4 (x - 12)

Solve for

x, 2 x - 12 = 4 (x - 12) : x = 18

Find age

Boy^{'} s age is : 18

Father^{'} s age is : 36

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