Owen invested 63,000 in an account paying an interest rate of 6.5% compounded continuously. Assuming no deposits or withdrawals are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach 159,600?

Lösung

Ow e n in v es t e d 63, 000 in an a cco u n t p a y in g an in t eres t r a t e o f 6.5% co m p o u n d e d co n t in u o u s l y . A ss u min g n o d e p os i t s or w i t h d r a w a l s a re ma d e, h o w l o n g w o u l d i t t ak e, t o t h e n e a res t t e n t h o f a ye a r, f or t h e v a l u e o f t h e a cco u n t t o re a c h 159, 600 ?

Time : 14.3

Schritte zur Lösung

Translate the problem into an equation:

159600 = 63000 e^{0.065 t}

Löse nach

t, 159600 = 63000 e^{0.065 t} : t = 14.3

Time : 14.3