en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

David is four years older than Joaquin. The sum of their ages is 36. FIND EACH PERSONS AGE

Solution

David is four years older than Joaquin. The sum of their ages is 36. FIND EACH PERSONS AGE

Solution

David^{'} s age is : 20

Joaquin^{'} s age is : 16

Solution steps

Translate the problem into an equation:

x + x - 4 = 36

Solve for

x, x + x - 4 = 36 : x = 20

Find age

David^{'} s age is : 20

Joaquin^{'} s age is : 16

Popular Examples

bea is 4 years younger than nicole. in 10 years bea will be twice as old as nicole age now mary is 6 years older than her sister kelly. the sum of their ages is 48. how old is kelly Today a man is five times as old as his son. In 6 years’ time he will be 3 times as old as his son. How old is the man today?AJ is 6 years younger than his sister Ella. Five years ago, the sum of their ages is 50 . How old are they 7 years from now?Ishaan is 3 times as old as Christopher and is also 14 years older than Christopher. How old is Christopher?