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Phổ biến Word Problems >

Aubrey invested 61,000 in an account paying an interest rate of 1.9% compounded continuously. Assuming no deposits or withdrawals are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach 73,600?

Lời Giải

A u b rey in v es t e d 61, 000 in an a cco u n t p a y in g an in t eres t r a t e o f 1.9% co m p o u n d e d co n t in u o u s l y . A ss u min g n o d e p os i t s or w i t h d r a w a l s a re ma d e, h o w l o n g w o u l d i t t ak e, t o t h e n e a res t t e n t h o f a ye a r, f or t h e v a l u e o f t h e a cco u n t t o re a c h 73, 600 ?

Lời Giải

Time : 9.88

Các bước giải pháp

Translate the problem into an equation:

73600 = 61000 e^{0.019 t}

Giải

t, 73600 = 61000 e^{0.019 t} : t = 9.88

Time : 9.88

Ví dụ phổ biến

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