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Popular Word Problems >

The sum of the squares of two consecutive positive odd integers is 202. find the integers.

Solution

T h e s u m o f t h e s q u a res o f tw o co n sec u t i v e p os i t i v e o dd in t e g ers i s 202. f in d t h e in t e g ers .

Solution

The numbers : 9, 11

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 2

A.T.Q.:

x^{2} + (x + 2)^{2} = 202

Solve

x^{2} + (x + 2)^{2} = 202 : x = 9, x = - 11

Select positive solutions:

9

x + 2 = 9 + 2 = 11

The numbers : 9, 11

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