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Popular Word Problems >

If the area of a rectangle is 491a^9b^2 and the length is 491a^4b, find the width

Solution

I f t h e a re a o f a rec t an g l e i s 491 a^{9} b^{2} an d t h e l e n g t h i s 491 a^{4} b, f in d t h e w i d t h

Solution

w i d t h : a^{5} b

Solution steps

Given:

a re a : a^{9} b^{2}

l e n g t h : a^{4} b

Rectangle Width

w

, given

A re a = a^{9} b^{2}, l = a^{4} b : w = a^{5} b

w i d t h : a^{5} b

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