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Joshua is twice as old as his brother Carlo. In 10 years, the sum of their ages will be 45. How old are they now?

Solution

Joshua is twice as old as his brother Carlo. In 10 years, the sum of their ages will be 45. How old are they now?

Solution

Carlo^{'} s age is : 8 \frac{1}{3}

Joshua^{'} s age is : 16 \frac{2}{3}

Solution steps

Translate the problem into an equation:

2 x + 10 + x + 10 = 45

Solve for

x, 2 x + 10 + x + 10 = 45 : x = \frac{25}{3}

Find age

Carlo^{'} s age is : 8 \frac{1}{3}

Joshua^{'} s age is : 16 \frac{2}{3}

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