Lauren's age is half of Joe's age. Emma is four years older than Joe. Pat is 4/5 of Lauren's and Joe's age squared. The sum of Lauren, Emma, and Joe's age is 234. How old is Pat? Also Joe was lying about his age and is 5 years older

Solution

L a u re n^{'} s a g e i s ha l f o f J o e^{'} s a g e . E mma i s f o u r ye a rs o l d er t han J oe . P a t i s \frac{4}{5} o f L a u re n^{'} s an d J o e^{'} s a g e s q u a re d . T h e s u m o f L a u re n, E mma, an d J o e^{'} s a g e i s 234. Ho w o l d i s P a t ? A l so J oe w a s l y in g ab o u t hi s a g e an d i s 5 ye a rs o l d er

Pat^{'} s age is : 36 \frac{4}{5}

étapes des solutions

Translate the problem into an equation:

\frac{1}{2} x + x + 4 + x = 234

Solutionner pour

x, \frac{1}{2} x + x + 4 + x = 234 : x = 92

Trouver Pat's age

: 36 \frac{4}{5}

Pat^{'} s age is : 36 \frac{4}{5}