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Beliebt Word Problems >

Two years ago, a father was four times older than his son. In twelve years’ time, he will be twice as old as his son. Find the ages of both the father and his son.

Lösung

Tw o ye a rs a g o, a f a t h er w a s f o u r t im es o l d er t han hi s so n . I n tw e l v e ye a rs ’ t im e, h e w i ll b e tw i ce a s o l d a s hi s so n . F in d t h e a g es o f b o t h t h e f a t h er an d hi s so n .

Lösung

Father^{'} s age is : 30

Boy^{'} s age is : 9

Schritte zur Lösung

Translate the problem into an equation:

x - 2 = 4 (y - 2), x + 12 = 2 (y + 12)

x - 2 = 4 (y - 2), x + 12 = 2 (y + 12) : x = 30, y = 9

Father^{'} s age is : 30

Boy^{'} s age is : 9

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