The sum of two numbers is equal to 63, and their 差 is equal to12. Find the numbers.

解

T h e s u m o f tw o n u mb ers i s e q u a l t o 63, an d t h e i r d i ff ere n ce i s e q u a l t o 12. F in d t h e n u mb ers .

The numbers : 37 \frac{1}{2}, 25 \frac{1}{2}

解答ステップ

Represent the numbers with

x and y

number 1 : x

number 2 : y

A.T.Q.:

x + y = 63

x - y = 12

x + y = 63, x - y = 12 : x = \frac{75}{2}, y = \frac{51}{2}

仮分数を帯分数に変換する:

\frac{75}{2} = 37 \frac{1}{2}

仮分数を帯分数に変換する:

\frac{51}{2} = 25 \frac{1}{2}

The numbers : 37 \frac{1}{2}, 25 \frac{1}{2}