the sum of 3 consecutive even numbers is 1208. what are the numbers

解

t h e s u m o f 3 co n sec u t i v e e v e n n u mb ers i s 1208. w ha t a re t h e n u mb ers

The numbers : 400 \frac{2}{3}, 402 \frac{2}{3}, 404 \frac{2}{3}

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + x + 2 + x + 4 = 1208

解く

x + x + 2 + x + 4 = 1208 : x = \frac{1202}{3}

x + 2 = \frac{1202}{3} + 2 = \frac{1208}{3}

x + 4 = \frac{1202}{3} + 4 = \frac{1214}{3}

仮分数を帯分数に変換する:

\frac{1202}{3} = 400 \frac{2}{3}

仮分数を帯分数に変換する:

\frac{1208}{3} = 402 \frac{2}{3}

仮分数を帯分数に変換する:

\frac{1214}{3} = 404 \frac{2}{3}

The numbers : 400 \frac{2}{3}, 402 \frac{2}{3}, 404 \frac{2}{3}