What is the value of -(2cos(pi))/(sqrt(2-4sin(pi))) ?

The value of -(2cos(pi))/(sqrt(2-4sin(pi))) is square root of 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-(2cos(pi))/(sqrt(2-4sin(pi)))

- \frac{2 cos ( π )}{2 - 4 sin ( π )}

2

Decimal Notation

1.41421 \dots

Solution steps

- \frac{2 cos ( π )}{2 - 4 sin ( π )}

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= - \frac{2 ( - 1 )}{2 - 4 \cdot 0}

Simplify

- \frac{2 ( - 1 )}{2 - 4 \cdot 0} : 2

- \frac{2 ( - 1 )}{2 - 4 \cdot 0}

Remove parentheses:

(- a) = - a

= - \frac{- 2 \cdot 1}{2 - 4 \cdot 0}

Multiply the numbers:

2 \cdot 1 = 2

= - \frac{- 2}{2 - 4 \cdot 0}

2 - 4 \cdot 0 = 2

2 - 4 \cdot 0

Apply rule

0 \cdot a = 0

= 2 - 0

Subtract the numbers:

2 - 0 = 2

= 2

= - \frac{- 2}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - (- \frac{2}{2})

Cancel

\frac{2}{2} : 2

\frac{2}{2}

Cancel

\frac{2}{2} : 2

\frac{2}{2}

Apply radical rule:

2 = 2^{\frac{1}{2}}

= \frac{2}{2 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{1}}{2 ^{\frac{1}{2}}} = 2^{1 - \frac{1}{2}}

= 2^{1 - \frac{1}{2}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= 2^{\frac{1}{2}}

Apply radical rule:

2^{\frac{1}{2}} = 2

= 2

= 2

= - (- 2)

Apply rule

- (- a) = a

= 2

= 2

tan (\frac{12}{9})

sinh (\frac{7}{18})

190 cos (2 0^{\circ})

9 arccos (- 1)

cos (\frac{2 π}{3} + \frac{3 π}{4})

What is the value of -(2cos(pi))/(sqrt(2-4sin(pi))) ?
The value of -(2cos(pi))/(sqrt(2-4sin(pi))) is square root of 2