What is the value of arccos(cos(3.2)) ?

The value of arccos(cos(3.2)) is (10pi-16)/5

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arccos(cos(3.2))

arccos (cos (3.2))

\frac{10 π - 16}{5}

Decimal Notation

176.65

Solution steps

arccos (cos (3.2))

= arccos (cos (\frac{16}{5}))

Use the inverse trig property:

\frac{10 π - 16}{5}

arccos (cos (\frac{16}{5}))

For

0 \leq x \leq π, a rccos (cos (x)) = x

Rewrite using trig identities:

cos (\frac{16}{5}) = cos (\frac{10 π - 16}{5})

cos (\frac{16}{5})

cos (x) = cos (2 π - (x))

= cos (2 π - \frac{16}{5})

= cos (\frac{10 π - 16}{5})

= arccos (cos (\frac{10 π - 16}{5}))

0 \leq \frac{10 π - 16}{5} \leq π

= \frac{10 π - 16}{5}

= \frac{10 π - 16}{5}

csc (27 0^{\circ}) + sec (24 0^{\circ})

arctan (\frac{600}{800})

sin (17 9^{\circ})

cos (arcsin (\frac{4}{5}) + \frac{π}{3})

cos (11 3^{\circ})

What is the value of arccos(cos(3.2)) ?
The value of arccos(cos(3.2)) is (10pi-16)/5