What is the value of cos(0+pi) ?

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cos(0+pi)

cos (0 + π)

- 1

Solution steps

cos (0 + π)

Simplify

= cos (π)

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

= - 1

4 sec^{2} (\frac{π}{4}) tan^{2} (\frac{π}{4}) + 2 sec^{4} (\frac{π}{4})

cos (π - 1) \cdot 0.2

\frac{cos ( 0.002 ) - 1}{0.00 2 ^{2}}

\frac{cos ( 2 ( 0.001 ) ) - cos ( 0.001 )}{0.00 1 ^{2}}

cot (arcsin (\frac{12}{13}))