What is the value of sin(arccos((-sqrt(3))/2)) ?

The value of sin(arccos((-sqrt(3))/2)) is 1/2

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sin(arccos((-sqrt(3))/2))

sin (arccos (\frac{- 3}{2}))

\frac{1}{2}

Decimal Notation

0.5

Solution steps

sin (arccos (\frac{- 3}{2}))

Rewrite using trig identities:

sin (arccos (\frac{- 3}{2})) = 1 - (\frac{- 3}{2})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (\frac{- 3}{2})^{2}

= 1 - (\frac{- 3}{2})^{2}

Simplify

= \frac{1}{2}

4 sin (\frac{π}{6}) cos (\frac{π}{6})

\frac{228}{tan ( 1 5 ^{\circ} )}

arcsin (\frac{51}{55})

sin (8 0^{\circ}) cos (5 0^{\circ}) - cos (8 0^{\circ}) sin (5 0^{\circ})

24 cos (6 0^{\circ})

What is the value of sin(arccos((-sqrt(3))/2)) ?
The value of sin(arccos((-sqrt(3))/2)) is 1/2