What is the value of 5sin(-pi) ?

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5sin(-pi)

5 sin (- π)

0

Solution steps

5 sin (- π)

Rewrite using trig identities:

sin (- π) = 0

sin (- π)

Use the following property:

sin (- x) = - sin (x)

sin (- π) = - sin (π)

= - sin (π)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= - 0

Simplify

= 0

= 5 \cdot 0

Simplify

= 0

- 2 sin (\frac{π}{4})

2 sinh (0)

- csc (6 0^{\circ})

2 cos^{2} (4 8^{\circ}) - 1

sin (\frac{3 π}{5}) cos (\frac{4 π}{15}) - cos (\frac{3 π}{5}) sin (\frac{4 π}{15})